Question

A rock dropped on the moon will increase its speed from 0 m/s to 4.9 m/s in about 3 seconds. What is the acceleration of the rock

Answer 1

a = change in v/t
= vf - vi / t
= 4.9 - 0 / 3
= 1.6 m/s^2

Answer 2

Acceleration of the rock is 1.64 m/s²

Step-by-step explanation:

It is given that,

Initial speed of the rock, u = 0

Final speed of the rock, v = 4.9 m/s

Time taken by a rock, t = 3 seconds

We have to determine the acceleration of the rock. The acceleration of the rock is equal to the rate of change of velocity. Mathematically, it can be written as :

`a=(v-u)/(t)`

`a=(4.9\ m/s-0)/(3\ s)`

`a=1.633\ m/s^2`

`a=1.64\ m/s^2`

So, the acceleration of the rock is 1.64 m/s². Hence, this is the required solution.