asked 170k views
2 votes
Find the zeroes of polynomial x² -(√3+1)x+√3

asked
User Kumputer
by
8.5k points

1 Answer

6 votes
x² - √3x -x +√3

x(x-√3) -(x-√3)

(x-√3)(x-1)

zeroes are x-√3 = 0
x = √3

and x-1 =0
x =1
answered
User Shweta
by
8.2k points
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