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Point C is the center of the circle. If angle ACB measures (3x + 1)° and arc AB measures (2x + 7)°, find x

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m(\widehat{ACP}) = m(\overset{\frown}{AB}) \\ \\ \Longrightarrow~~~(3x+1)^o = (2x+7)^o \\ \\ 3x+1 = 2x+7 \\ \\ 3x - 2x = 7-1 \\ \\ \boxed{x = 6^o }



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