Question

The discriminant of a quadratic equation is the value b2 – 4ac. What is the value of the discriminant of 0 = –2x2 + 6x + 13?

Answer 1

Let

D-------> discriminant of a quadratic equation

we know that

The discriminant of a quadratic equation is equal to

`D=b^(2) -4ac`

In this problem

we have

`-2x^(2) + 6x + 13=0\\ \\ a=-2\\ b=6\\c=13`

Substitute the values in the formula above

`D=6^(2) -4*(-2)*(13)`

`D=36+104`

`D=140`

therefore

the answer is

the value of the discriminant is
`140`

Answer 2

ax^2 + bx + c = 0
-2x^2 + 6x + 13 = 0

a = -2
b = 6
c = 13

b^2 - 4ac

6^2 - 4(-2)(13)
= 36 - (-104)
= 36 + 104
= 140

The value of the discriminant is 140.