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Sinxcosy = 1/2 (sin(x+y)+cos (x-y))

Sinxcosy = 1/2 (sin(x+y)+cos (x-y))
asked 168k views
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Sinxcosy = 1/2 (sin(x+y)+cos (x-y))

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User Rishawn
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1 Answer

4 votes
(1/2) [SIN(X-Y)-SIN(X+Y)]= COS(X)SIN(Y)
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User Manoj Agarwal
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