asked 222k views
2 votes
What is the sum of the first nine terms of the geometric series where a1 = 7 and r = −3?

1 Answer

3 votes
Sum of terms of a geometric series
Sn = a1 (r^n-1)/(r-1)
a1 = 1st term = 7
n = number of terms = 9
r = common ratio = -3

Sn = 7 ((-3)^8-1)/(-3-1) = -11480
Hence the sum is -11480.
answered
User Md Alamin
by
8.4k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.