Question

The sum of a number and two times a smaller number is 62. three times the bigger number exceeds the smaller number by 116. the bigger number is . the smaller number is

Answer 1

x+2y=62
3x-2y=116

solving the simultaneous equations by multiplying first equation by 3;
3x+6y=186
3x-y=116

Subtracting equation II from equation I;
7y=70
y=10
Replacing y in equation I;

x+20=62
x=42

Bigger number is 42 and smaller number is 20.