How many grams of O2(g) are needed to completely burn 55.9 g of C3H8(g)?

Question

asked Jul 11, 2017 140k views

1 Answer

Goran Vasic · Answer 1 · 2017-07-16T07:27:29+0000

The balanced chemical reaction will be:

C3H8 + 5O2 = 3CO2 +4H2O

We are given the amount of propane gas to be burned. This will be our starting point.

55.9 g C3H8 ( 1 mol C3H8 / 44.1 g C3H8 ) ( 5 mol O2/1 mol C3H8)(32 g O2 / 1 mol O2) = 202.81 g O2