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An = cos(npi/2). If convergent find limit of sequence?

An = cos(npi/2). If convergent find limit of sequence?
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An = cos(npi/2). If convergent find limit of sequence?

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User RavuAlHemio
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The sequence is: cos(π/2), cos (π ), cos (3π/2), cos ( 2π ),...
or: 0,-1,0,1,0,-1,0,1,... Since cos (nπ/2) oscillates between -1 and 1 as n tends to infinity, this sequence is divergent (limit does not exist).
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User Kevin Hsiao
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