Question

A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g. a. Calculate the number of moles of C12H22O11 contained in the sample

Answer 1

Molar mass sucrose C₁₂H₂₂O₁₁ = 342 g/mol

1 mole ----------- 342 g
? mol ------------- 1.202 g

moles = 1.202 *1 / 342

moles = 1.202 / 342

= 0.00351 moles of sucrose

hope this helps!

Answer 2

moles = 0.0035 moles

Step-by-step explanation:

In order to use this, we need to use the expression to calculate the moles of any compound, which is:

n = m/MM (1)

Where:

n: moles

m: mass of the compound (in grams)

MM: Molecular mass of compound (grams per mole)

Now, we have the mass of the sucrose, but we do not have the molecular mass. To calculate it, we need to use the atomic weights of each indivual element of the compound. In this case, C, H and O.

The atomic weights that I'll use will be rounded, and they are:

C = 12 g/mol

H: 1 g/mol

O: 16 g/mol

Now, let's calculate the molar mass of sucrose

MMSucrose:

C = 12 * 12 = 144

H = 1 * 22 = 22

O = 16 * 11 = 176

MM = 144 + 22 + 176 = 342 g/mol

We have the molar mass, let's calculate the moles now, using (1):

n = 1.202 / 342

n = 0.0035 moles