For this case suppose we have a function of the form: 
 y = f (x) 
 Where, 
 x: independent variable 
 y: dependent variable 
 We have then that the value of the function for x = c is: 
 f (c) = 0 
 Therefore, we have that: 
 The point (c, 0) belongs to f (x)
 x-c is a common factor of f (x) because the function evaluated at x = c is equal to zero. 
 x = c is a root of f (x) so c is a zero of the function f (x) 
 Answer: 
 D. All three statements are true.