Factorise 30y^2 - 33yz - 18z^2

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asked Oct 6, 2017 192k views

1 Answer

Zaratustra · Answer 1 · 2017-10-10T16:40:32+0000

Hello,

30y²-33yz-18z²=3(5y+2z)(2y-3z)

Since

Let's assume u=y/z

30y²-33yz-18z²=3(10y²-11yz-6z²)
=3z²((10(y/z)²-11(y/z)-6)
=3z²*(10u²-11u-6)
=3z²*(5u+2)(2u-3)
=3z²*(5y/z+2)(2y/z-3)=3z²(5y+2z)(2y-3z)/z²
=3(5y+2z)(2y-3z)

Factorise 30y^2 - 33yz - 18z^2

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