Question

A gas has an initial volume of 24.6 L at a pressure of 1.90 atm and a temperature of 335 K. The pressure of the gas increases to 3.50 atm, and the volume of the gas increases to 31.3 L.

Answer 1

The problem can be solved by using the formula associated with the gas laws. It is as follows:

PV/T

Given:

P1 = 1.9 atm
V1 = 24.6 L
T1 = 335 K

P2 = 3.5 atm
V2 = 31.3 L
T2 = ?

Substituting the given:

P1V1/T1 = P2V2/T2
(1.9 * 24.6)/335 = (3.5 * 31.3)/T2
T2 = 785.18 K