The number of possible different 12-letter arrangements of the letters in the word “TRIGONOMETRY” is represented by

Question

asked Feb 27, 2017 128k views

1 Answer

Paul Ramsey · Answer 1 · 2017-03-03T12:06:21+0000

We will use formula for Permutations with repetition:
P(n, m1,m2,m3) = n! / m1! · m2! · m3!
In the word TRIGONOMETRY we have repetitions of letters: T, R and O.
P=
(12!)/(2!*2!*2!)= (12*11*10*9*8*7*6*5*4*3*2*1)/(2*1*2*1*2*1) =

(12!)/(2!*2!*2!)= (12*11*10*9*8*7*6*5*4*3*2*1)/(2*1*2*1*2*1) =

= 59,875,200

The number of possible different 12-letter arrangements of the letters in the word “TRIGONOMETRY” is represented by

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

No related questions found

Categories

Other Questions