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Calculate the magnitude of the horizontal vector that is 100 units long and is oriented at 45 degrees

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5 votes
Your question is somewhat twisted up. We would be justified in simply asking you to correct the question. But I think I know what you're talking about, so I'll try to answer it.

A horizontal vector is one that's oriented at an angle of zero degrees, not 45 degrees. I think what you want is the horizontal component of the vector that you're describing.

Its horizontal component is 100 cos(45) = 100 / √2 = 70.71 units.
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User LuckyLikey
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