asked 206k views
0 votes
How many atoms of phosphorus are in 9.20 mol of copper(II) phosphate?

1 Answer

4 votes
The number of atoms of phosphorus in copper (II) phosphate [Cu3 (PO4)2] is determined by multiplying first 9.20 by 2 since there are two phosphorus atoms in the compound and multiplying again with Avogadro's number. The answer is 1.108 x 10^25 atoms. 
answered
User Tomas Nikodym
by
7.6k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.