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What is the equation of the line that passes through (5, -2) and (-3, 4)? 3x - 4y - 7 = 0 3x + 4y - 7 = 0 -3x + 4y - 7 = 0

What is the equation of the line that passes through (5, -2) and (-3, 4)? 3x - 4y - 7 = 0 3x + 4y - 7 = 0 -3x + 4y - 7 = 0
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What is the equation of the line that passes through (5, -2) and (-3, 4)?

3x - 4y - 7 = 0
3x + 4y - 7 = 0
-3x + 4y - 7 = 0

asked
User Teknotica
by
7.6k points

1 Answer

1 vote
Hello,
answer B

y+2=(4+2)/(-3-5)(x-5)
==>y+2=-3/4 (x-5)
==>4y=-3x+7
==>3x+4y-7=0


answered
User Ishu
by
7.5k points
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