Question

If y varies with x^2 and y=36, when x=3, what is y when x=5?

Answer 1

`y=k x^(2) \\ 36=k * (3) ^(2) = 9k \\ k=36/9=4`
Therefore, when x = 5,

`y=4 * (5)^(2) = 4*25 = 100`