Question

6x-2y=33
4x+3y=9 What would x and y be?

Answer 1

To find the variables of the equations, use systems of equations.

First get rid of one variable. Let's get rid of the y by multiplyin both equations nad then adding them.

`(6x-2y=33)3`

`(4x+3y=9)2`


`18x-6y=99`

`8x+6y=18`

`26x=117`

Solve for x:

`(26x)/(26) = (117)/(26)`

`x=4.5`

Now you have x! Plug x into one quation and solve for y:

`6(4.5)-2y=33`

`27-2y=33`

`(-2y)/(-2) = (6)/(-2)`

`y=-3`


`x=4.5, y=-3`

Answer 2

`6x-2y=33 \\\\ 6x=33+2y \\\\ \boxed{x=(2y+33)/(6)} \\\\ 4x+3y=9 \\\\ 4*(2y+33)/(6)+3y=9 \\\\ 2*(2y+33)/(3)+3y^((3)=9^((3) \\\\ 2(2y+33)+9y=27 \\\\ 4y+66+9y=27 \\\\ 13y=27-66 \\\\ 13y=- 39 \\\\ \boxed{y=-(39)/(13)=-3} \\\\ x=(2*(-3)+33)/(6) \\\\ x=(-6+33)/(6) \\\\ x=(27)/(6) \\\\ \boxed{x=(9)/(2)}`