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Let C be between D and E. Use the segment addition postulate to solve for m. DC = 6m − 21 CE = 7m − 18 DE = 65 a. –3 c. 13 b. 5 d. 8

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User Qqbt
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1 Answer

5 votes
D-C-E

DC = 6m - 21
CE = 7m - 18
DE = 65

DC + CE = DE
6m - 21 + 7m - 18 = 65
13m - 39 = 65
13m = 65 + 39
13m = 104
m = 104/13
m = 8

DC = 6m - 21 = 6(8) - 21 = 48 - 21 = 27
CE = 7m - 18 = 7(8) - 18 = 56 - 18 = 38

answered
User SinusGob
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