The answer is C=6p3 + 29p2 + 22p – 21
To calculate the product, we need to multiply each member of each multiplier:
(2p + 7)(3p2 + 4p – 3) = 2p · 3p² + 2p · 4p + 2p · -3 + 7 ·3p² + 7 · 4p + 7 · -3
= 6p³ + 8p² - 6p + 21p² + 28p - 21
= 6p³ + 8p² + 21p² + 28p - 6p -21
= 6p³ + 29p² + 22p - 21
Therefore, the product of (2p + 7)(3p2 + 4p – 3) is 6p³ + 29p² + 22p -21