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When Emma pushes a bag with a force of 27 newtons, the coefficient of kinetic friction between the bag and the floor is 0.23. What is the normal force acting on the bag by the floor?

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This can be answered by manipulating the formula for the coefficient of kinetic friction, which is as follows:

Let: μ = coefficient of kinetic friction
F = force
N = normal force

μ = F / N

Substituting the given values:

0.23 = 27N / N
N = 27 / 0.23
N = 117.39 N
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User Lyricat
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