Question

The average kinetic energy of 1 mole of a gas at 25 degrees Celsius is:

Answer 1

The mass of a molecule is very very small but there is many molecules and they all have kinetic energy. First, we have to assume that the gas is ideal. Kinetic energy of an ideal gas is only a function of moles and temperature. Hence:
KE=(3/2)nRT = (3/4)(1mole)(8.314J/molK)(25+273.15)K
= 3718.22J or 3.7KJ

Answer 2

Answer: 3716.4 Joules

Step-by-step explanation:

Average kinetic energy is defined as the average of the kinetic energies of all the particles present in a system. It is determined by the equation:

`K=(3nRT)/(2)`

K= kinetic energy

n= number of moles = 1

R= gas constant = 8.314 J/Kmol

T= temperature in Kelvin =
`25^0C=(25+273)K=298K`

Putting in the values, we get

`K=(3* 1* 8.314* 298)/(2)=3716.4Joules`

Thus average kinetic energy of 1 mole of a gas at 25 degrees Celsius is 3716.4 Joules