Question

A 2000 kg car experiences a constant braking

force of 10,000 N, and comes to be a stop in 6
sec.
What would be the distance traveled by the
car in coming to rest?

Answer 1

Solving for acceleration:

F = ma
10000 = 2000*a
a = 5 m/s^2

Solving for velocity:

Vf = Vi + a(t)
0 = Vi - (5)(6)
Vi = 30 m/s

Solving for displacement or distance:

S = Vi*t - 1/2 * a * t^2
S = 30(6) - 1/2 (5)(6)^2
S = 90m

The car would have traveled 90m before coming to rest.