Question

If the largest angle of a triangle is 120 degrees and it is included between sides of 1.5 and 0.5, what is the largest side of the triangle to the nearest tenth?

Answer 1

1.8

Explanation:

Answer 2

c²=a²+b²-2·a·b·cos(C)

c²=(1.5)² + (0.5) -2 ·(l·5) ·(0.5) ·cos(120°)

c²= 3.25

c= √3.25

c=1.802775638

To nearest tenth, c=1.8