Question

The sum of two numbers is 13. Two times the first number minus three times the second number is 1. If you let x stand for the first number and y for the second number, what are the two numbers?

Answer 1

x+y= 13
2x-3y= 1
This can be found by using a system but I will try this method:
x=13-y
We replace it on the second one:
2(13-y) + y = 13
26-2y + y=13
-y= -13
y= 13