Question

What is the equation of the line that passes through the points (–2, 2) and (0, 5)?

Answer 1

Hello,

The slope= (5-2)/(0+2)=3/2

Equation is y-2=3/2(x+2) or y=3x/2+5

Answer 2

The equation of line is given by

`y=(3)/(2)x+5`

Explanation:

We have been given the points (–2, 2) and (0, 5) and we have to find the equation of the line.

Let us first find the slope of the line using the formula

`m=(y_2-y_1)/(x_2-x_2)`

On substituting the values, we get

`m=(5-2)/(0+2)`

`m=(3)/(2)`

Now, using the point slope form, the equation of line is given by

`y-y_1=m(x-x_1)\\y-2=(3)/(2) (x+2)\\\\y-2=(3)/(2)x+3\\\\y=(3)/(2)x+5`

Therefore, the equation of line is given by

`y=(3)/(2)x+5`