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Given the equation (x+2)(x+3)(x+5)=(x+2)(x-3)(x+5), what can we conclude about the solutions

1 Answer

4 votes
Hello,

(x+2)(x+3)(x+5)=(x+2)(x-3)(x+5)
==>(x+2)(x+5)(x+3-(x-3))=0
==>(x+2)(x+5)*6=0

==>x=-2 or x=-5

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