Question

If an excess of sulfric acid reacts with 23.0 grams of sodium chloride how many grams of hydrochloric acid are produced?

2H2SO4 + 4NaCI -> 2H2SO4 + 4HCI

Answer 1

NaCl = 58.44 g/mol
H₂SO₄ = 98.0 g/mol

H₂SO₄ + 2 NaCl = 2 HCl + Na₂SO₄

98.0 g H₂SO₄ -----------> 2 x 58.44 g NaCl
? g H₂SO₄ ------------> 23.0 g NaCl

Mass of H₂SO₄ = 23.0 x 98.0 / 2 x 58.44

Mass of H₂SO₄ = 2254 / 116.88

=> 19.284 g of H₂SO₄

hope this helps!