Decompose -6x/(x+4)(x-4) into partial fractions

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asked Dec 19, 2017 86.6k views

1 Answer

FeFiFoFu · Answer 1 · 2017-12-23T21:44:44+0000

Hello,

Integration fractions?

-6x/((x+4)(x-4))=A/(x+4)+B/(x-4)=((A+B)x-4A+4B)/((x+4)(x-4))
==> A+B=-6 and -4A+4B=0
==>A=B=-3

Answer -3/(x+4)-3/(x-4)

Decompose -6x/(x+4)(x-4) into partial fractions

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