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4t + 2u2 - u3 ; t=2 u=1 ( I can't input exponents; the second '2' in 2u2 is an exponent, and the '3' in u3 is, too.)

4t + 2u2 - u3 ; t=2 u=1 ( I can't input exponents; the second '2' in 2u2 is an exponent, and the '3' in u3 is, too.)
asked 20.4k views
4 votes
4t + 2u2 - u3 ; t=2 u=1

( I can't input exponents; the second '2' in 2u2 is an exponent, and the '3' in u3 is, too.)

asked
User Maurizio
by
8.0k points

1 Answer

6 votes
9, I believe.
4(2)+2(1)^2-(1)^3 (^ just means to the power of "exponent")
8+2-1=9
answered
User Anatolii Shuba
by
8.2k points
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