What mass of sodium carbonate is required to prepare 2.00 l of 0.250 M Ma2CO3 solution

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asked Oct 4, 2017 48.0k views

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Russell Cohen · Answer 1 · 2017-10-08T13:08:43+0000

Molar mass Na₂CO₃ = 106.0 g/mol

M(Na₂CO₃) = molarity x volume x molar mass

M(Na₂CO₃) = 0.250 x 2.00 x 106.0

M (Na₂CO₃) = 53 g

hope this helps!

What mass of sodium carbonate is required to prepare 2.00 l of 0.250 M Ma2CO3 solution

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