asked 164k views
4 votes
The factorization of 8x3 – 125 is (2x – 5)(jx2 + kx + 25). What are the values of j and k?

asked
User MoDJ
by
8.0k points

2 Answers

3 votes

Answer:

j=4 k=10 on edg ;)

Explanation:

answered
User Jnmonette
by
8.2k points
5 votes
If you would like to find the values of j and k, you can do this using the following steps:

8x^3 - 125 = (2x - 5) * (jx^2 + kx + 25)
8x^3 - 125 = 2jx^3 + 2kx^2 + 50x - 5jx^2 - 5kx - 125

8x^3 = 2jx^3
4x^3 = jx^3
j = 4

2kx^2 + 50x - 5jx^2 - 5kx = 0
2kx^2 + 50x - 20x^2 - 5kx = 0
2kx^2 - 20x^2 + 50x - 5kx = 0
2kx - 20x + 50 - 5k = 0
2x(k - 10) = 5k - 50
2x(k - 10) = 5(k - 10)
k = 10

The correct result would be: j = 4 and k = 10.
answered
User Nikhil Yadav
by
8.6k points
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