Question

The quadratic equation y=2x^2-px+6 has equal roots. Find the possible values of p.

Answer 1

`\Delta=0\\ \Delta=(-p)^2-4\cdot2\cdot6=p^2-48\\ p^2-48=0\\ p^2=48\\ p=√(48) \vee p=-√(48)\\ p=4\sqrt3 \vee p=-4\sqrt3`