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Determine the vertex of the following quadratic equation... h(x) = 7(x-5)^2

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User Micans
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1 Answer

4 votes
Hello,

h(x)=7(x-5)²
h'(x)=14(x-5)
h'(x)=0 <=> x=5
The vertex is (5,0) is a minimum.

answered
User Forcedfx
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