Question

A rectangular garden is 6 feet long and 4 feet wide. A second rectangular garden has dimensions that are double the dimensions of the first garden. What is the percent of change in perimeter from the first garden to the second garden?

Answer 1

First rectangular garden:

length = 6 feet and width =4 feet

Perimeter of first garden =2(l+w) =2(6+4) =20 feet...........(1)

Second rectangular garden:

second rectangular garden has dimensions that are double the dimensions of the first garden

length =2* 6 =12 feet and width =2* 4 =8 feet

Perimeter of second garden =2(12+8) =2*20=40 feet

`percentage change in perimeter = (perimeter of second garden-perimeter of first garden)/(perimeter of first garden ) *100`

% change = (40-20)/20 *100 =100

% change =100%