Given h(x)=√5-x, the range of h, in inequality notation, is

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asked Mar 22, 2017 211k views

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Amsvartner · Answer 1 · 2017-03-28T05:28:29+0000

assuming that the 5-x is under te sqrt sign

you cannot have sqrt of a negative
find where it equals zero
5-x=0
5=x

the limit is 5=x

x has to be greater than x
to infinity
D=x

Given h(x)=√5-x, the range of h, in inequality notation, is

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