Question

How do I solve 17(x+5)=0

Answer 1

ok so if you ahve ab=0
assume a and b=0 because 0 times x=0

17(x+5)=0
17 is not equal to zero
therefor
x+5=0
minus 5
x=-5

Answer 2

Use the distributive problem to distribute the 17 to the values in the parentheses. 17(x + 5) = 0, 17x + 17(5) = 0, 17x + 85 = 0. Subtract 85 from both sides of the equal sign. 17x = -85. Divide both sides of the equal sign by 17, x = -5.