Question

952 grams of ammonium carbonate are dissolved to make 1750 mL of solution

Answer 1

(%m/v) =mass of solute (in g) / volume of solution (in mL) x 100

= 952 g (NH4)2CO3 / 1750 mL x 100

= 0.544 x 100

(%m/v) = 54.4 g /mL or 54.4% concentration of ammonium carbonate
solution