The temperature of a sample of water increases from 20 degrees Celsius to 46.6 degrees Celsius as it absorbs 5650 calories of heat. What is the mass of the sample

Question

asked May 4, 2017 13.4k views

1 Answer

← Prev Question Next Question →

Ask a Question

Taper · Answer 1 · 2017-05-08T22:59:04+0000

ΔT = 46.6 - 20

ΔT = 26.6ºC

Specific heat of water is 1.0 cal/g °C

Q = m * C * ΔT

5650 = m * 1.0 * 26.6

5650 = m * 26.6

m = 5650 / 26.6

m = 212.4 g

hope thips helps!

The temperature of a sample of water increases from 20 degrees Celsius to 46.6 degrees Celsius as it absorbs 5650 calories of heat. What is the mass of the sample

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

Related questions

Categories

Other Questions