Question

Find the equation of the line with gradient 3/4 which passes through point (1,1)

Answer 1

Let the equation of the line be: y = mx + c
Since m is the gradient, m = 3/4
∴ y =
`(3)/(4)` + c
c is the y-intercept, and to find it, substitute the coordinate (1, 1) into the equation:
1 =
`(3)/(4)` × 1 + c
c = 1 -
`(3)/(4)`
c =
`(1)/(4)`
∴ y =
`(3)/(4)`x +
`(1)/(4)`

I hope the calculations are correct...