Question

Find the measure of a supplement of a 20 3/4 degrees

Answer 1

`supplement = 20 \ 3/4 + x =180 \\20 \ 3/4 + x =180 \\x = 180 - 20 \ 3/4 \\\boxed{x = 159.25}`

Answer 2

`20 (3)/(4)= (83)/(4) \\ \\ 180^((4)-(83)/(4)= (720-83)/(4)=\boxed{(637)/(4)=159 (1)/(4)-the \ suplement}`