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Please factor this and find the domain and show work

6c-3/3c^2-12

1 Answer

6 votes

(6c - 3)/(3c^(2) - 12) = (3(2c) - 3(1))/(3(c^(2)) - 3(4)) = (3(2c - 1))/(3(c^(2) - 4)) = (2c - 1)/(c^(2) - 4) = (2c - 1)/(c^(2) + 2c - 2c - 4) = (2c - 1)/(c(c) + c(2) - 2(c) - 2(2)) = (2c - 1)/(c(c + 2) - 2(c + 2)) = (2c - 1)/((c - 2)(c + 2))

Domain: ±2
answered
User Glenmore
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