Question

If 3.00 g of limestone reacted, what mass of calcium chloride would be produced?

A) Calcium chloride
B) Carbon dioxide
C) water

Answer 1

a) CaCO₃ + 2 HCl = CaCl₂ + H₂O + CO₂
↓ ↓
1 mole 1 mole

molar mass :

CaCO₃ = 100.0 g/mol CaCl₂ = 111 g/mol

100 g CaCO₃ ------------- 111 g caCl₂
3.00 g CaCO₃ --------------- ?

3.00 * 111 / 100 =

333 / 100 = 3.33 g of CaCl₂
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b) molar mass CO₂ = 44.0 g/mol

100 g CaCO₃ ---------- 44.0 g CO₂
3.00 g CaCO3 ------------- ?

3.00 * 44 / 100 =

132 / 100 = 1.32 g of CO2
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c) molar mass H₂O = 18.0 /mol

100 g CaCO3 ------- 18.0 g
3.00 g CaCO3 ------- ?

3.00 * 18.0 / 100 =

54 / 100 = 0.54 g of H₂O
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hope this helps!