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Subtract 3/y-2 - 1/y+3

1 Answer

3 votes
to subtract fractions, we need a common denominator.


(3)/(y-2) -
(1)/(y+3)

the common denominator will be (y-2)(y+3)


(3(y+3)-1(y-2))/((y-2)(y+3))

(3y + 9 - y + 2)/((y-2)(y+3))

(2y + 11)/((y-2)(y+3))

The answer above will be the simplified form.
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User Nihilarian
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