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Given 16.2 grams of substance Y, if the substance absorbs 2722 joules of energy and the specific heat of the substance is 9.22 J/g·°C, what is the final temperature of the subst…
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Given 16.2 grams of substance Y, if the substance absorbs 2722 joules of energy and the specific heat of the substance is 9.22 J/g·°C, what is the final temperature of the subst…
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Jun 17, 2017
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Given 16.2 grams of substance Y, if the substance absorbs 2722 joules of energy and the specific heat of the substance is 9.22 J/g·°C, what is the final temperature of the substance if the initial was 26 degrees Celsius?
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Velmurugan
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Since the substance absorbs heat, it is expected that the temperature will rise. The formula for the internal energy of a substance is given by the equation:
ΔU = mCpΔT
where:
ΔU = internal energy
m = mass of substance
Cp = specific heat capacity of substance
ΔT = change in temperature
ΔU = 2722 Joules = 16.2 grams (9.22 J/g-°C) (Tf - 26°C)
This gives a final temperature of
Tf = 44.22 °C
Yevgeniy P
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Jun 24, 2017
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