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4 votes
Find the grams of iron in 79.2 g of Fe2O3.

asked
User Anew
by
7.3k points

1 Answer

4 votes
First you find the RFM (Relative Formula Mass) of Fe2O3
Fe2 = 56 x 2
= 112
O3 = 16 x 3
= 48

112 + 48 = 160

Moles = mass/RFM
= 79.2/160
=0.495

Then you rearrange the formula
Mass= moles x RFM
= 0.495 x 112
= 55.44 g
(To find mass of Iron have to use RFM of total iron in the substance example Fe2 ^^)


answered
User Nicholas Rees
by
7.9k points

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