Question

X squared + ysquared-6y=-5

Answer 1

Standard Form of the circle:


`x^(2) +(y-3) ^(2) =14`

For y:

y=3 (+/-)
`√(-x) ^(2) +14`

For x:

x=
`\sqrt{-y ^(2) } +6y+5 and - √(-y) ^(2) +6y+5`