Consecutive integers are 1 more than the other.
If one of them is x.
The three would be x, x + 1, x + 2
Since the sum are 138
x + (x + 1) + (x +2) = 138
x + x + 1 + x +2 = 138
x + x + x + 1 + 2 = 138
3x + 3 = 138
3x = 138 - 3
3x = 135
x = 135/3
x = 47.
So the numbers are, x, x + 1, x + 2, = 47, 47 + 1 = 48, 47 + 2 = 49
The integers are 47, 48, and 49.