Question

A gas is cooled from 365 K to 285 K while its volume changes from 12.8 L to 9.9 L. The initial pressure of the gas is 1.9 atm. The final pressure of the gas, rounded to the nearest tenth, is atm.

Answer 1

A gas is cooled from 365 K to 285 K while its volume changes from 12.8 L to 9.9 L. The initial pressure of the gas is 1.9 atm. The final pressure of the gas, rounded to the nearest tenth, is atm.

Answer 2

The correct answer to the question is : 1.9 atm.

Step-by-step explanation:

Let us consider the pressure, volume and temperature of a gas are denoted as P,V and T respectively.

Initial condition : Final condition:

`P_(1) = 1.9\ atm`
`P_(2) =\ ?`

`V_(1) =\ 12.8\ L`
`V_(2) =\ 9.9\ L`

`T_(1)=\ 365\ K`
`T_(2) =\ 285\ K`

From combined equation of gas, we know that-

`(P_(1)V_(1))/(T_(1) ) =\ (P_(2)V_(2))/(T_(2))`

⇒
`P_(2) =\ (P_(1)V_(1))/(T_(1) ) * (T_(2) )/(V_(2) )`

`=\ (1.9* 12.8)/(365)* (285)/(9.9)\ atm`

`=\ 1.91814\ atm`

`=\ 1.9\ atm` [ans]

Hence, the final pressure is 1.9 atm.